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这是我期末考试可能会考到的一道题目,拜托大虾们帮我解释一下该怎么做:
% j8 D4 s$ A7 J+ Z* T8 y/ s+ U To resolve overlapping resonances in a 2D spectrum of a protein acquired in 24 hours at 500MHz, a spectroscopist decided to measure a 5D spectrum using a 600MHz spectrometer. how long does he need to accumulate the 5D spectrum in order to reach the same signal-to-noise ratio as in the original 2D spectrum? r* c+ @3 A' ~- ~% j/ v9 v! X, c5 n
0 C" _4 A, E/ G o5 ^9 t2. a 3D HNCA spectrum of a membrane protein in 500 mM NaCl aqueous buffer, using a spectrometer of 500 MHz with maximal signal-to-noise ratio S/N=2:1, has been obtained after 24 hours of data acquisition. which change in experimental setup would provide the lagest increase in S/N? a) Repeating the experiment in the same time (24 hours) using a spectrometer operating at 600MHz. OR b) Repeating the same experiment for the next 24 hours and summing two 1H spectra together
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真郁闷死了!碰上个印度教授,英语口音重得很,完全听不懂他讲什么!只有上专业论坛来求助专家了!拜托大家给我这个菜鸟好好解释一下! 谢谢了!
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