On acetylation (OH group was changed to OCOCH3 group), the alpha6 k# u' v2 @' f7 S% I- k
carbon will show a downfield shift while the belta carbon will show a
% Q! y* n! {! p* A% c9 ]upfield shif. ) u- Q. v; s$ j* A7 `" ~5 t
; N t. l* e5 t4 u
See the following article how to revise a structure reported before just using the above rule! ' w P% O8 K7 G% @# ^' K; ? , @5 ?9 h- V; s, {1 e' t7 AOne compound with C-6 OH, C-7 OH (compound IV in the article): chemical shift values of C-6 79.3 ppm, C-7 76.2 ppm were known. 1 o0 Q1 F. [' k/ B9 h; N * B: j* c7 y$ ?7 V" ], J' JAnother compound with one OH group acetylated: it could be C-6 OAc, C-7
) _* D$ m; e2 p0 Q4 D( J2 \* TOH (compound I in the article) or could be C-6 OH, C-7OAc (compound II
6 @( P( m3 ^( P# W3 din the article). The chemical shifts of the two carbons are 78.1 and8 ?, r0 }" n8 \
80.5. How to determine which carbon (C-6 or C-7) has the OAC group?
1 H. p/ Y+ w6 d/ o' A" ?, F . f& Y: } A6 f5 c9 \The auhors resovled the problem: + X4 S1 }& ?' C9 @& [
' J$ ?9 i2 r7 _( Y
If C-6 (80.5) and C-7 (78.5) were right, meaning both the chemical
1 ?2 I7 @- q5 @1 ]shifts of C-6 (79.3 to 80.5) and C-7 (76.2 to 78.5) were increased.8 F9 c5 Y( r9 G( o% {4 F
That assupmtion violates the above rule. 8 m, T9 [+ j% H4 s) b! p
1 e/ d& T1 ]1 w1 r. ]
So chemical shift of C-6 was not 80.5 but 78.5, chemical shift of C-7 was not 78.5 but 80.5. 4 ~+ ~5 F( D6 Q1 B7 g ; }7 v/ ~- ?+ ~/ z: U
C-6 (78.5) and C-7 (80.5) meaned that C-6 shifted to highfield (from! i Q; f7 Z# Y$ `, e& p0 {! R
79.3 to 78.5), C-7 shifted to lowfield (from 76.2 to 80.5). Logically,
5 T/ S* c- `& s( V2 e- j0 ?it was the C-7 with the OAC group (compound II), not the C-6 with the
7 F. v6 W* W' zOAC group (compound I). 3 L: s% F" {1 f, m+ `; [
. R% q" c( B7 d6 Z5 P2 B4 S0 P. bSimple, logic structural revision published in 1981!