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[求助]NMR检测小分子配体与蛋白相互作用

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发表于 2010-10-18 18:42:26 | 显示全部楼层 |阅读模式

刚接触NMR,想用来检测一下一种三个苯环的小分子配体与一种三万KDa的蛋白的相互作用,

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请教各位大侠,是做小分子的H谱呢?还是做大分子的H谱?

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做的话对于溶剂有什么要求吗?蛋白用什么溶剂呢?小分子用DMSO溶解可以吗?

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各位大侠帮帮忙,不胜感激啊

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发表于 2010-10-18 23:59:29 | 显示全部楼层
应该是用std 实验吧。
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 楼主| 发表于 2010-10-19 12:22:57 | 显示全部楼层
什么事STD实验啊?大侠能详细解释一下吗?小弟初次接触NMR
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发表于 2010-10-19 20:45:31 | 显示全部楼层
同问。蛋白的核磁咋做?
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发表于 2010-10-19 23:54:37 | 显示全部楼层
 

STD NMR

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STD NMR ! S( U/ @7 k8 v experiments detect magnetization that is transferred from a receptor protein + W/ I! p q0 t+ r to a bound ligand. Only bound ligands show STD effects. The experiment may be 4 u& H; x" ^; m! ]$ ~ combined with virtually any other NMR experiment, and therefore is well suitable $ ~% u2 v+ Y5 \ to tackle even very complex problems. In particular, in combination with multidimensional 1 M" V' v9 S1 j1 y6 {) C/ N NMR a full characterization of a bound ligand out of a mixture is straightforward. + _, W7 k0 z4 ? STD NMR is extremely robust and gives maximal effects at protein to ligand ratios $ I! @, M& J( r9 S greater than ca. 1:100. It follows that less than 1 nmol of protein is necessary * y8 {' t! {5 ]7 z4 o( I/ R4 Y0 b for screening. With the availability of so called cryo probes it will be possible + {! t9 k) ^* g to work with hundred pmol amounts of protein. The dissociation constant should & j6 y" q" E- _# Z: A, F be in the range between nM and mM. Therefore, STD NMR covers at least two orders 8 @ H6 s. n! T; y5 p5 j* } of magnitudes more for dissociation constants than trNOE experiments. From competitive - F- t$ M/ g/ S STD experiments dissociation constants may be derived.

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/ k3 @2 N( H9 k1 d Schematic : v3 e3 \1 ?2 h display of the STD NMR effect. Saturation of the protein leads to a direct saturation 7 Y( P5 d; P% ? of those parts of ligand(s) in direct contact to the protein. By exchange between / f6 \; a! Z: r bound and free state the saturation is transported to solution and detected ( O% L m* T' m- r by subtracting a spectrum with saturation from a normal spectrum.
4 r$ @7 u( r5 d }: N- W( {7 X( z# H; ` STD NMR gives precise information about the binding epitope of the ligand. This ; b) k4 Q8 d! i+ C+ H is very important information for the design of a potent drug. The optimal drug ' p9 b' F: r- H0 v1 s- n( M is of optimal size and optimal shape. The size is deduced from STD NMR, and F# r$ y P& l9 n8 N the shape is delivered by trNOE experiments.

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