找回密码
 马上注册

扫一扫,访问微社区

搜索
热搜: mestrenova
查看: 2630|回复: 4

[求助]NMR检测小分子配体与蛋白相互作用

[复制链接]
发表于 2010-10-18 18:42:26 | 显示全部楼层 |阅读模式

刚接触NMR,想用来检测一下一种三个苯环的小分子配体与一种三万KDa的蛋白的相互作用,

; A) {# p$ q. y( E+ q. r, K/ S0 a

请教各位大侠,是做小分子的H谱呢?还是做大分子的H谱?

- y0 _2 c% F0 m6 m" \# f

做的话对于溶剂有什么要求吗?蛋白用什么溶剂呢?小分子用DMSO溶解可以吗?

( V% S4 n( }, l, E

各位大侠帮帮忙,不胜感激啊

回复

使用道具 举报

发表于 2010-10-18 23:59:29 | 显示全部楼层
应该是用std 实验吧。
回复 支持 反对

使用道具 举报

 楼主| 发表于 2010-10-19 12:22:57 | 显示全部楼层
什么事STD实验啊?大侠能详细解释一下吗?小弟初次接触NMR
回复 支持 反对

使用道具 举报

发表于 2010-10-19 20:45:31 | 显示全部楼层
同问。蛋白的核磁咋做?
回复 支持 反对

使用道具 举报

发表于 2010-10-19 23:54:37 | 显示全部楼层
 

STD NMR

# a$ k+ n3 m: }0 V& i$ X

STD NMR 0 u5 Q6 j( }) u% \1 E) J7 t$ D experiments detect magnetization that is transferred from a receptor protein 9 [: [- N" p! N to a bound ligand. Only bound ligands show STD effects. The experiment may be J9 v! A1 O- g, q: } combined with virtually any other NMR experiment, and therefore is well suitable % z2 _7 D" |* Z; ^! n& G$ j to tackle even very complex problems. In particular, in combination with multidimensional , ?3 G, A Q0 L/ L; V" w0 D NMR a full characterization of a bound ligand out of a mixture is straightforward. 0 y( C8 f7 E! h9 a" g T1 t STD NMR is extremely robust and gives maximal effects at protein to ligand ratios # B8 l1 N" `1 ^( U greater than ca. 1:100. It follows that less than 1 nmol of protein is necessary - |' _9 z1 O( _ for screening. With the availability of so called cryo probes it will be possible # ]# w$ R- [; m1 c# D to work with hundred pmol amounts of protein. The dissociation constant should : {. f, i1 |; A+ A3 w, \0 c be in the range between nM and mM. Therefore, STD NMR covers at least two orders # ?* i% U- [1 L M3 y% I+ ~; J! s of magnitudes more for dissociation constants than trNOE experiments. From competitive % o7 b: v: Q6 A4 ~& K STD experiments dissociation constants may be derived.

8 l0 s, n: Z% D- l9 L


- f- c2 d4 g3 U0 ]% q

* y0 |8 n" M Y) J1 ^7 ^! K& j3 O. r9 x Schematic y6 I5 O- ^6 c; m! x5 T! i5 W display of the STD NMR effect. Saturation of the protein leads to a direct saturation 1 [" h$ h( J, J K of those parts of ligand(s) in direct contact to the protein. By exchange between 8 g" F$ N1 g+ M6 L' @ bound and free state the saturation is transported to solution and detected 9 i! z* r' V% d# D7 `! e by subtracting a spectrum with saturation from a normal spectrum.
3 @9 M. m, Q; I STD NMR gives precise information about the binding epitope of the ligand. This ! A0 d* {0 K; @' \! ^2 l( _ is very important information for the design of a potent drug. The optimal drug + \) g; V' b0 x, A is of optimal size and optimal shape. The size is deduced from STD NMR, and ' ?/ W6 y( v* b8 [- ^ the shape is delivered by trNOE experiments.

回复 支持 反对

使用道具 举报

您需要登录后才可以回帖 登录 | 马上注册

本版积分规则

Archiver|手机版|中国核磁共振论坛

GMT+8, 2025-7-16 06:00

Powered by Discuz! X3.5

© 2001-2024 Discuz! Team.

快速回复 返回顶部 返回列表